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MessagePosté le: Lun 20 Mar - 06:28 (2017)    Sujet du message: Cyclicity Of Remainders Pdf Free Répondre en citant




Cyclicity Of Remainders Pdf Free > bit.ly/2mjo2u2

























































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ReplyGMAT...Club's...website...has...not...been...reviewed...or...endorsed...by...GMACAfter..that,..we..can..use..the..property..Last..two..digits..of..(&a1)^(&b)..will..be..[Last..digit..of..a*b]1..Let..us..try..and..apply..this..concept..in..the..given..question..Last..two..digits..of..57^69..=..Last..two..digits..of..57*(57^2)^34..=..Last..two..digits..of..57*(.49)^34..=..Last..two..digits..of..57*(.01)^17..=..Last..two..digits..of..57*(.01)..=..57....8)..What..is..the..remainder..when..767^1009..is..divided..by..25?..Ans:..Remainder..of..a..number..from..25..will..be..the..same..as..the..remainder..of..the..last..two..digits..of..the..number..from..25+12*12!)..../....13]....=....-1....=....12........3)How....do....you....find....the....remainder....when....7^26....is....divided....by....100?....Ans:....Finding....out....the....remainder....from....100,....is....the....same....as....finding....out....the....last....two....digits....of....a....number....Last....two....digits....of....7^1....are....07....Last....two....digits....of....7^2....are....49....Last....two....digits....of....7^3....are....43....Last....two....digits....of....7^4....are....01....After....this,....the....same....pattern....will....keep....on....repeatingPlease....note....that....576....=....24^2....There....are....couple....of....methods....of....solving....thisSearch...Register...GMAT...Club...Tests...Decision...Tracker...My...Rewards...New...posts...Unanswered...GMAT...Club...Daily...Prep...Thank...you...for...using...the...timer...-...this...advanced...tool...can...estimate...your...performance...and...suggest...more...practice...questionsLBS....19Vineet..Patawari..June..11,..2014..at..9:07..amThanks..for..such..a..wonderful..remarkReply

You...are...here:...GMAT...Club...Forum...Index...GMAT...GMAT...Quantitative...Section...or...or...or...Not...a...Member?...It...is...currently...19...Mar...2017,...22:28...2^1..=..22^3..=..82^5..=..322^2..=..42^4..=..162^6..=..64Cyclicity..is..2If...we...put,...k...=...1,...we...get...101...+...1...=...102,...which...is...divisible...by...6I..think..you..may..find..it..valuable..(esp..those..replies..with..Kudos).Want..to..see..all..other..topics..I..dig..out?..Follow..me..(click..follow..button..on..profile)Hard...questions...part...2;...4.All...are...free...for...GMAT...Club...membersRitwik...October...30,...2015...at...9:30...pmHow...do...you...solve...this...question:...Find...the...units...digit...in:...12^(4n+1)+23^(4n+1)+34^(4n+3)-47^(4n-2)...Reply

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